1.4 Indexing and Slicing

1.4.1 1 D Python List

my_list = ['a0','b1','c2','d3','e4','f5','g6','h7']

Syntax	Result		Note
`my_list[0]`	First element	`'a0'`
`my_list[-1]`	Last element	`'h7'`
`my_list[0:3]`	Index 0 to 2	`['a0','b1','c2']`	Give \(3-0 = 3\) elements
`my_list[1:6]`	Index 1 to 2	`['b1', 'c2', 'd3', 'e4', 'f5']`	Give \(6-1 = 5\) elements
`my_list[1:6:2]`	Index 1 to 5 in steps of 2	`['b1', 'd3', 'f5']`	Give every other of \(6-1 = 5\) elements
`my_list[1:]`	Index 1 to the end	`['b1', 'c2', 'd3', 'e4', 'f5', 'g6', 'h7']`	Give \(length-1 = 7\) elements
`my_list[:5]`	Index 0 to 5	`['a0', 'b1', 'c2', 'd3', 'e4']`	Give \(5-0 = 5\) elements
`my_list[5:2:-1]`	Index 5 to 3	`['f5', 'e4', 'd3']`	Give \(5-2 = 3\) elements
`my_list[::-1]`	Reverses the list	`['h7', 'g6', 'f5', 'e4', 'd3', 'c2', 'b1', 'a0']`

1.4.2 2D Numpy Array

import pandas as np
my_list_np = np.array([['A0', 'A1', 'A2', 'A3', 'A4'],
                       ['B0', 'B1', 'B2', 'B3', 'B4'],
                       ['C0', 'C1', 'C2', 'C3', 'C4']])

Syntax	Result	Result
`my_list_np[0]`	1^st row	`['A0','A1','A2','A3','A4']`
`my_list_np[1]`	2^nd row	`['B0','B1','B2','B3','B4']`
`my_list_np[0,1]`	1^st row, 2^nd element	`A1`
`my_list_np[1,1:3]`	2^nd row, elements 2 to 3	`['B2','B3','B4']`
`my_list_np[1,1:]`	2^nd row, elements 2 to 3	`['A0','B1','C2']`