Third Sylow theorem
As proven in the previous section, the number of Sylow
p-subgroups of G is given by |G : NG(P)|,
where P is any Sylow p-subgroup of G. This number,
denoted by np is a factor of |G|. In addition,
we have the following information about np.
Theorem 1
For each prime p, np
º 1 (mod p).
Proof
Recall that for any p-subgroup
H of G, we have |G : H| º
|NG(H) : H| (mod p). Let P be any Sylow
p-subgroup, and we have |G : P| º
|NG(P) : P| (mod p). Note that P <
NG(P) < G. Also, since P is a Sylow p-subgroup,
|G : P| is relatively prime to p Þ
|G : NG(P)| = |G : P| / |NG(P) : P|
º 1 (mod p).